Hello from France !
it is not difficult to make some back-of-a-virtual-envelope calculations to roughly predict the total bellows draw required to frame a tight portrait. I say : "virtual envelope" since we'll not compute anything at all except mentally estimate some rough values

No math required ! If you can mentally convert inches into millimetres (and vice-versa) or can mentally covert used LF lens prices labeled in Euro or Dollars into Sterling Pounds, then you are all set for what follows
If we consider in the 5x4 format that we need to reach the magnification ratio M=1:2 = 0.5, it means that we'll be able to frame a subject of size 10x8 inches i.e. 250x200 mm. This corresponds to a tight portrait.
For a given magnification factor M = (image size)/(object size), the
additional bellows draw or bellows extension "ext" beyond the focal point (where images of far distant objet will focus sharp) is
"ext" = M . f
where "f" is the focal length in use; the formula is valid for all lenses whatever their design might be.
The other information needed is the flange focal distance which is proper to each lens.
For quasi-symmetrical lens like an apo-symmar, apo ronar, etc.. i.e. anything which is not a telephoto, the flange focal distance is close to the focal length;
hence with such a lens you need about 1.5 times the focal length in order to reach the magnification ratio M=1/2 = 0.5
If the total bellows draw is 324 mm, the max focal lengh for a symmetrical lens design @M=0.5 and (f+ext)=324 is 2/3 of 324, i.e. 2x108 = 216mm say 210 mm.
in this situation with M=0.5, the distance between the subjet and lens is f(1+1/M) = about 3 f = 610 mm. This is probably too close for a traditional "respectful" portrait ; howerver, for a record cover of a traditional & "so British" Rock-Pop Group of the last century, I would suggest getting much closer if possible
now we are left with the hard rule of photographic perspective :
perspective rendition is independant of the focal length, only the placement of the lens (actually : the distance to the entrance pupil)
defines the projection of a 3-D object on film. The choice of a suitable focal length will
of course define the external frame in the final image.
Now consider a 360 tele arton lens ; I own one and I'm very happy with it. Its flange focal distance is 210 mm.
At M=0.5, the additional extension "ext" will be about 360/2 = 180 mm. Plus 210 of flange focal distance makes a total bellows draw of (210 + 180) = 390. Still too much for a maximum of 324 ; hence let's take it the other way : 324-210 = 114 = ext = Mx360 hence M = about 1/3 is the closest we can reach.
With 324 mm of total bellows draw, our brave Toyo and our brave tele arton will allow us to reach M= about 1/3
The object frame will be 3x4 by 3x5 inches i.e. about 300x370 mm. distance to the subject will be f(1+1/M) = 360x(1+3) = 1,44 metre ; this is more acceptable for a "classical" portrait.